A gas is taken through the cycle A to B to C | vedclass

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(A) In a $P-V$ diagram,the net work done during a cyclic process is equal to the area enclosed by the cycle.Since the cycle $A 	o B 	o C 	o A$ is c

Vedclass · Accepted Answer

$1000$

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(A) In a $P-V$ diagram,the net work done during a cyclic process is equal to the area enclosed by the cycle.Since the cycle $A 	o B 	o C 	o A$ is clockwise,the work done is positive.The area of the triangle $ABC$ is given by:$	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$Base $= V_C - V_A = (7 - 2) 	imes 10^{-3} \ m^3 = 5 	imes 10^{-3} \ m^3$Height $= P_B - P_C = (6 - 2) 	imes 10^5 \ Pa = 4 	imes 10^5 \ Pa$$	ext{Work Done} = \frac{1}{2} 	imes (5 	imes 10^{-3}) 	imes (4 	imes 10^5) = \frac{1}{2} 	imes 20 	imes 10^2 = 1000 \ J$.

$A$ gas is taken through the cycle $A \to B \to C \to A$ as shown in the figure. What is the net work done by the gas in $J$?

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